1/(n-3)=n+4/(n^2-5n+6)+1/(n-2)

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Solution for 1/(n-3)=n+4/(n^2-5n+6)+1/(n-2) equation: 



1/(n-3)=n+4/(n^2-5n+6)+1/(n-2)

We move all terms to the left:

1/(n-3)-(n+4/(n^2-5n+6)+1/(n-2))=0

We can not solve this equation

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